The equation AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl

  1. Detailed information about the equation AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl
    The equation shows the reaction between the chemical compounds Aluminum chloride (AlCl3) and Sodium hydroxide (NaOH) to produce Aluminum hydroxide (Al(OH)3) and Sodium chloride (NaCl).

  2. Reaction conditions
    This reaction takes place at normal temperatures. Additionally, this reaction requires the presence of a water environment, as NaOH and AlCl3 need to be dissolved in water to form a solution before starting the reaction.

  3. Reaction process
    Aluminum chloride, when exposed to water, will undergo significant dissociation, resulting in Al3+ and Cl-. Similarly, Sodium hydroxide will also dissociate significantly, producing Na+ and OH-. These ions then recombine with each other in a new way to create Aluminum hydroxide and Sodium chloride.

  4. Observed phenomena
    When the reaction occurs, we will see the precipitation phenomenon of Aluminum hydroxide appearing in the solution. Aluminum hydroxide is white and insoluble in water, therefore it forms precipitate particles and settles at the bottom of the container. Additionally, the remaining solution will contain Sodium chloride, a substance soluble in water, so no other obvious phenomena will occur.

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